AnswerEX3-a: Difference between revisions
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<nowiki>[[</nowiki>''dog (Walter) Ʌ enjoy-watching-soccer-together (Lisa,Tom)'']] = | <nowiki>[[</nowiki>'''dog (Walter) Ʌ enjoy-watching-soccer-together (Lisa,Tom)''']] = ''false'' <br/> | ||
because <nowiki>[[</nowiki>''dog (Walter'' | because <nowiki>[[</nowiki>'''dog (Walter)''']]= ''true'' <br/> | ||
::because I(''Walter'')= < | ::because I('''Walter''')= <''Walter''> and <''Walter''> is an element of I('''dog''') <br/> | ||
but <nowiki>[[</nowiki>''enjoy-watching-soccer-together (Lisa,Tom)'']] = | but <nowiki>[[</nowiki>'''enjoy-watching-soccer-together (Lisa,Tom)''']] = ''false'' <br/> | ||
::because I(''Lisa'')= < | ::because I('''Lisa''')= <''Lisa''>, I('''Tom''')= <''Tom''> and <''Lisa,Tom''> is NOT in the set of I('''enjoy-watching-soccer-together'''). <br/> | ||
Revision as of 09:45, 29 January 2013
Sentence: Walter is a dog and Lisa and Tom enjoy watching soccer together.
Here the interpretation in predicate logic notation:
[[dog (Walter) Ʌ enjoy-watching-soccer-together (Lisa,Tom)]] = false
because [[dog (Walter)]]= true
- because I(Walter)= <Walter> and <Walter> is an element of I(dog)
- because I(Walter)= <Walter> and <Walter> is an element of I(dog)
but [[enjoy-watching-soccer-together (Lisa,Tom)]] = false
- because I(Lisa)= <Lisa>, I(Tom)= <Tom> and <Lisa,Tom> is NOT in the set of I(enjoy-watching-soccer-together).
- because I(Lisa)= <Lisa>, I(Tom)= <Tom> and <Lisa,Tom> is NOT in the set of I(enjoy-watching-soccer-together).
Conjunction (Ʌ): Both atomic formulae have to be true in order for the complex formula to be true.