AnswerEX1-d: Difference between revisions
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*[[Creation_of_the_World|Link to the current exercise]] | *[[Creation_of_the_World|Link to the current exercise]] | ||
+[[Formulae_and_their_interpretation|Link back to exercise 2]] | |||
*[[Interpretation_of_formulae_with_connectives|Link back to exercise 3]] | *[[Interpretation_of_formulae_with_connectives|Link back to exercise 3]] | ||
*[[NMTS-Group9|Link to the Wiki Page]] | *[[NMTS-Group9|Link to the Wiki Page]] |
Revision as of 13:27, 29 January 2013
U = {Alice,Paul,Tom,Lisa,Walter}
Names:
I (Alice) = Alice
I (Paul) = Paul
I (Tom) = Tom
I (Lisa) = Lisa
I (Walter) = Walter
Properties:
I (wants-to-live-in-Munich) = {<Alice>,<Paul>,<Tom>,<Lisa>}
I (lives-in-Berlin) = {<Alice>,<Paul>,<Tom>,<Lisa>}
I (lives-in-Munich) = {}
I (rather small) = {<Alice>,<Tom>}
I (tall) = {<Lisa>,<Paul>}
I (blonde) = {<Alice>,<Lisa>}
I (female) = {<Alice>,<Lisa>}
I (male) = {<Tom>,<Paul>}
I (likes-eating-shoes) = {<Walter>}
I (doesn't-care-about-sports) = {<Walter>}
I (bored-watching-soccer) = {<Tom>,<Paul>}
I (enjoys-watching-soccer) = {<Alice>,<Lisa>}
I(enjoys-watching-football) = {<Alice>,<Lisa>,<Paul>,<Tom>}
Relations:
I (son-of-someone) = {<Tom,Paul>,<Tom,Alice>}
I (daughter-of-someone) = {<Lisa,Paul>,<Lisa,Alice>}
I (mother-of-someone) = {<Alice, Lisa>,<Alice,Paul>}
I (father-of-someone) = {<Paul,Tom>,<Paul,Lisa>}
I (brother-of-someone) = {<Tom,Lisa>}
I (sister-of-someone) = {<Lisa,Tom>}
I (dog-of-someone) = {<Walter,Alice>,<Walter,Paul>,<Walter,Tom>,<Walter,Lisa>}
I (married-to-eachother) = {<Alice,Paul>}
I (enjoy-watching-football-together) = {<Alice,Paul>,<Alice,Lisa>,<Alice,Tom>,<Paul,Lisa>, <Paul,Tom>,<Tom,Lisa>}
Comment Sailer:
1) check the fonts.
2) brother-of, sister-of and married-to-eachother are symmetric relations, i.e., the pairs must also be in the relation in the other order.