AnswerEX2-b1: Difference between revisions
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I(Paul) = {Paul}, | I(Paul) = {Paul}, | ||
I(Lisa) | I(Lisa) = {Lisa} | ||
and | and | ||
Revision as of 19:18, 24 January 2013
father of someone (Paul,Lisa) = true,
because
I(Paul) = {Paul},
I(Lisa) = {Lisa}
and
<Paul,Lisa> is a set of I(father of someone).