AnswerEX2-b1: Difference between revisions
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'''father-of-someone'''('''paul''','''lisa''') = ''true'', | |||
because | because | ||
I( | I('''Paul''') = <''Paul''>, | ||
I(lisa) = | I('''lisa''') = <''Lisa''> | ||
and | and | ||
< | <''Paul,Lisa''> '''is''' in the set of I('''father-of-someone'''). | ||
====Navigation==== | ====Navigation==== | ||
*[[Formulae_and_their_interpretation|Link to the current exercise]] | *[[Formulae_and_their_interpretation|Link to the current exercise]] | ||
Latest revision as of 12:29, 15 May 2013
father-of-someone(paul,lisa) = true,
because
I(Paul) = <Paul>,
I(lisa) = <Lisa>
and
<Paul,Lisa> is in the set of I(father-of-someone).