AnswerEX3-a: Difference between revisions
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::because I(lisa)= lisa, I(tom)= tom and <lisa,tom> is NOT an element of the set I(enjoy-watching-soccer-together). <br/> | ::because I(lisa)= lisa, I(tom)= tom and <lisa,tom> is NOT an element of the set I(enjoy-watching-soccer-together). <br/> | ||
Conjunction (Ʌ): Both atomic formulae have to be true in order for the complex formula to be true. | |||
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*[[Interpretation_of_formulae_with_connectives|Link to the current exercise]] | *[[Interpretation_of_formulae_with_connectives|Link to the current exercise]] | ||
Revision as of 18:04, 27 January 2013
Here the interpretation in predicate logic notation:
dog (walter) Ʌ enjoy-watching-soccer-together (lisa,tom) = FALSE
because dog (walter)= TRUE
- because I(walter)= walter and <walter> is an element of the set I(dog)
- because I(walter)= walter and <walter> is an element of the set I(dog)
but enjoy-watching-soccer-together (lisa,tom) = FALSE
- because I(lisa)= lisa, I(tom)= tom and <lisa,tom> is NOT an element of the set I(enjoy-watching-soccer-together).
- because I(lisa)= lisa, I(tom)= tom and <lisa,tom> is NOT an element of the set I(enjoy-watching-soccer-together).
Conjunction (Ʌ): Both atomic formulae have to be true in order for the complex formula to be true.