ExerciseFOLSemantics-1a: Difference between revisions

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'''father-of-someone'''('''paul''','''lisa''') = ''true'' iff<br />
'''father-of-someone'''('''paul''','''lisa''') = ''true'' iff<br />
< I('''paul'''), I('''lisa''') > &isin; I('''father-of-someone''') iff<br />
< I('''paul'''), I('''lisa''') > &isin; I('''father-of-someone''') iff<br />
< ''Paul'', ''Lisa''> &isin  
< ''Paul'', ''Lisa''> &isin; {<''Paul, Tom''>,<''Paul, Lisa''>}.


Since this is the case, the formula is true.


I('''Paul''') = <''Paul''>,
====Navigation====


I('''lisa''') = <''Lisa''>
*[[Exercise_Semantics_of_Predicate_Logic|Link to the exercises on the computation of the interpretation]]
 
* the material for [[Textbook-chapters#Chapter_2:_Predicate_logic|chapter 2]]
and
* the overview over [[Textbook-chapters|all chapters]]
 
<''Paul,Lisa''> '''is''' in the set of I('''father-of-someone''').

Latest revision as of 14:38, 22 May 2013

father-of-someone(paul,lisa) = true iff
< I(paul), I(lisa) > ∈ I(father-of-someone) iff
< Paul, Lisa> ∈ {<Paul, Tom>,<Paul, Lisa>}.

Since this is the case, the formula is true.

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