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[[NMTS-Group5#Restricted_Quantifiers|Return to Excercise]]
[[NMTS-Group5#Restricted_Quantifiers|Return to Excercise]]


== Types Quantifiers 2d ==
== Types Quantifiers 2d ==
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[[NMTS-Group5#Different_types_of_Quantifiers|Return to Excercise]]
[[NMTS-Group5#Different_types_of_Quantifiers|Return to Excercise]]


== Scopal Ambiguity 3a ==
== Scopal Ambiguity 3a ==
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[[NMTS-Group5#Scopal_Ambiguity|Return to Excercise]]
[[NMTS-Group5#Scopal_Ambiguity|Return to Excercise]]


== Restricted Quantifiers 1c ==
== Restricted Quantifiers 1c ==
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[[NMTS-Group5#Restricted_Quantifiers|Return to Excercise]]
[[NMTS-Group5#Restricted_Quantifiers|Return to Excercise]]


== Types Quantifiers 2a ==
== Types Quantifiers 2a ==
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[[NMTS-Group5#Different_types_of_Quantifiers|Return to Excercise]]
[[NMTS-Group5#Different_types_of_Quantifiers|Return to Excercise]]


== Types Quantifiers 2b ==
== Types Quantifiers 2b ==
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[[NMTS-Group5#Different_types_of_Quantifiers|Return to Excercise]]
[[NMTS-Group5#Different_types_of_Quantifiers|Return to Excercise]]


== Restricted Quantifiers 1b ==
== Restricted Quantifiers 1b ==
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[[NMTS-Group5#Restricted_Quantifiers|Return to Excercise]]
[[NMTS-Group5#Restricted_Quantifiers|Return to Excercise]]


== Types Quantifiers 2c ==
== Types Quantifiers 2c ==
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[[NMTS-Group5#Different_types_of_Quantifiers|Return to Excercise]]
[[NMTS-Group5#Different_types_of_Quantifiers|Return to Excercise]]


== Restricted Quantifiers 1d ==
== Restricted Quantifiers 1d ==
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[[NMTS-Group5#Restricted_Quantifiers|Return to Excercise]]
[[NMTS-Group5#Restricted_Quantifiers|Return to Excercise]]


== Scopal Ambiguity 3b ==
== Scopal Ambiguity 3b ==

Revision as of 11:38, 9 April 2013

On this page, you can find the solutions to the excercises on Quantifiers.


Restricted Quantifiers 1a

Sorry, this is not correct.

In restricted quantifier notation, the "complete" semantic representation of the noun phrase (NP) appears in the restrictor (-> square brackets).

Return to Excercise






Types Quantifiers 2d

Ramon signs every sculpture he makes.


2b) Universal Quantifier

∀x (SCULPTURE (x) & MAKE (r, x) → SIGN (r, x))

"For every thing x, if x is a sculpture and x is made by Ramon (r) then x is signed by Ramon (r)."


Since Ramon makes and signs the sculptures, the corresponding variables are (r, x).


2c) Restricted Quantifier

[Every x: SCULPTURE (x) & MAKE (r, x)] SIGN (r, x)

Here, the N' is "sculpture he makes" and therefore belongs in square brackets together with the Quantifier every.


Return to Excercise







Scopal Ambiguity 3a

In this sentence, the scopal ambiguity is created by the two quantifiers everyone and someone.

When looking at the two pictures that try to help you, you can see two possible readings:

1. For every person there is, there is at least one other person who loves him / her.

2. There is one person that is loved by everyone else.

Return to Excercise







Restricted Quantifiers 1c

Sorry, this is not correct.

In restricted quantifier notation, the semantic representation of the noun phrase (NP) appears in the restrictor.


Return to Excercise







Types Quantifiers 2a

Sorry, this is not correct.

Existential quantifiers are used for sentences that represent something that exists.

Of course, you could argue that there is a Person x such that x is called Ramon and x makes (and then signs) sculptures - but this is not what we were going for.

Maybe you want to check the possible answers once more.

Return to Excercise







Types Quantifiers 2b

Yes, this is correct.

Check if there is another correct answer!

Return to Excercise







Restricted Quantifiers 1b

Yes, this is correct.

Return to Excercise






Types Quantifiers 2c

Yes, this is correct.

Check if there is another correct answer!


Return to Excercise






Restricted Quantifiers 1d

Sorry, this is not correct.

In restricted quantifier notation, the semantic representation of the noun phrase (NP) appears in the restrictor.

Return to Excercise






Scopal Ambiguity 3b

1. For every person there is at least one person who loves him / her:

∀x (PERSON (x) → ∃y (PERSON (y) & LOVE (x, y))


2. There is one person that is loved by everyone:

∃x (PERSON (x) → ∀y (PERSON (y) & LOVE (y, x))


Return to Excercise

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