Example solution for the ''Jane Eyre'' context: Difference between revisions

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{{DenL}}'''&not; female(edward) &and; husband-of(edward,bertha)'''{{DenR}} = ''1''<br />
{{DenL}}'''&not; female(edward) &and; husband-of(edward,bertha)'''{{DenR}} = ''1''<br />
iff {{DenL}}'''&not; female(edward)'''{{DenR}} = ''1'' and {{DenL}}'''husband-of(edward,bertha)'''{{DenR}} = ''1''<br />
iff {{DenL}}'''&not; female(edward)'''{{DenR}} = ''1'' and {{DenL}}'''husband-of(edward,bertha)'''{{DenR}} = ''1''<br />
iff {{DenL}}'''female(edward)'''{{DenR}} = ''0''and {{DenL}}'''husband-of(edward,bertha)'''{{DenR}} = ''1''.
Since both conditions are met (as shown in task 3), the formula is true in our model,
<hr />
Back to the [[Assignmentsheet_Logic_Summer_Term_2013|assignment sheet on chapter 2]].


== Second example formular ==
== Second example formular ==

Latest revision as of 22:27, 28 June 2013

Task 4

1. Combine your two formulæ from Task 3 into two complex formulæ. Use the connectives “¬”, “∧”, and “⊃”

2. Compute the truth value of these complex formulæ. (You don’t need to do the computation for the atomic formulæ again.)

First example formula

Formula: ¬ female(edward) ∧ husband-of(edward,bertha)

Interpretation:

[[¬ female(edward) ∧ husband-of(edward,bertha)]] = 1
iff [[¬ female(edward)]] = 1 and [[husband-of(edward,bertha)]] = 1
iff [[female(edward)]] = 0and [[husband-of(edward,bertha)]] = 1.

Since both conditions are met (as shown in task 3), the formula is true in our model,


Back to the assignment sheet on chapter 2.

Second example formular